# How do you use partial fraction decomposition to decompose the fraction to integrate (x^2-4)^-1?

${\left({x}^{2} - 4\right)}^{-} 1 i s \frac{1}{{x}^{2} - 4}$
Its partial fraction would be $\frac{1}{4} \left[\frac{1}{x - 2} - \frac{1}{x + 2}\right]$
Integration would give $\frac{1}{4} \left[\ln \left(x - 2\right) - \ln \left(x + 2\right)\right\}$
=$\frac{1}{4} \ln \left(\frac{x - 2}{x + 2}\right)$