How do you use cross multiplication to solve $\frac{2}{x+3}-\frac{1}{x+4}=0$ ?

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Answer 1 · 2014-11-04T16:06:55

$2/{x+3}-1/{x+4}=0$

by adding $1/{x+4}$ ,

$=> 2/{x+3}=1/{x+4}$

by cross multiplication,

$=> 2cdot(x+4)=1cdot(x+3)$

by multiplying out,

$=> 2x+8=x+3$

by subtracting $x$ ,

$=>x+8=3$

by subtracting $8$ ,

$=> x=-5$

I hope that this was helpful.

How do you use cross multiplication to solve \frac{2}{x+3}-\frac{1}{x+4}=0\frac{2}{x+3}-\frac{1}{x+4}=0?