How do you use a graphing utility to approximate the solutions of $6sin^2x-7sinx+2=0$ in the interval $[0,2pi)$ ?

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Answer 1 · 2017-11-14T19:27:41

See below.

If you graph $y=6sin^2x-7sinx+2$ , where the curve cuts the x axis or turns at the axis will be the solutions to $6sin^2x-7sinx+2=0$ .

These are $x ~~$ $0.524 , 0.730 , 2.412 , 2.618$

Graph of $y=6sin^2x-7sinx+2$

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How do you use a graphing utility to approximate the solutions of 6sin^2x-7sinx+2=06sin^2x-7sinx+2=0 in the interval [0,2pi)[0,2pi)?