How do you use a calculator to solve each equation on the interval #(0 <= x < 2pi)# for #cos(x) = 0.6#?

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How do you use a calculator to solve each equation on the interval #(0 <= x < 2pi)# for #cos(x) = 0.6#?

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Answer 1 · 2015-10-28T14:29:37

Solve #cos x = 0.6#

Ans: #+- 53^@13#

Explanation:

By calculator:
cos x = 0.6 --> #x = 53^@13#.
Trig unit circle gives another arc x that has the same cos value -->
cos x = 0.6 --> x = - 53^@13.
Answer: #x = +- 53^@13#

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How do you use a calculator to solve each equation on the interval #(0 <= x < 2pi)# for #cos(x) = 0.6#?

1 Answer

Explanation:

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