# How do you test the series Sigma rootn(n)/n from n is [1,oo) for convergence?

${\sum}_{n = 1}^{\infty} \frac{\sqrt[n]{n}}{n}$ diverges.
${\sum}_{n = 1}^{\infty} \frac{\sqrt[n]{n}}{n} > {\sum}_{n = 1}^{\infty} \frac{1}{n}$ and ${\sum}_{n = 1}^{\infty} \frac{1}{n}$ diverges so ${\sum}_{n = 1}^{\infty} \frac{\sqrt[n]{n}}{n}$ diverges also.