How do you test the series Sigma (n+1)/n^3 from n is [1,oo) for convergence?

${\sum}_{n = 1}^{\infty} \frac{n + 1}{n} ^ 3 = {\sum}_{n = 1}^{\infty} \frac{1}{n} ^ 2 + \frac{1}{n} ^ 3 = {\sum}_{n = 1}^{\infty} \frac{1}{n} ^ 2 + {\sum}_{n = 1}^{\infty} \frac{1}{n} ^ 3$