How do you take the derivative of # tan^3(2x-x^3)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer GiĆ³ Jun 3, 2015 I would use the Chain Rule deriving the #()^3# first, then the #tan# and finally the argument of the #tan#: #y'=3tan^2(2x-x^3)xx1/(cos^2(2x-x^3))xx(2-3x^2)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2152 views around the world You can reuse this answer Creative Commons License