How do you solve $y=x^2-6x-1$ using the quadratic formula?

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Answer 1 · 2018-08-07T08:55:46

$x=3+-sqrt10$

$x=(-b+-sqrt(b^2-4ac))/(2a)$
where your quadratic equation is $y=ax^2+bx+c$

$x=(6+-sqrt((-6)^2-4(1)(-1)))/(2times1)$

$x=(6+-sqrt(36+4))/2$

$x=(6+-sqrt40)/2$

$x=(6+-2sqrt10)/2$

$x=3+-sqrt10$

How do you solve y=x^2-6x-1y=x^2-6x-1 using the quadratic formula?