How do you solve #(y-8)+6=15#?

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Answer 1 · 2016-03-08T12:48:05

#y=7#

#(y-8)+6=5#

Subtract #6# both sides

#rarr(y-8)6-6=5-6#

#rarr(y-8)=-1#

Remove brackets

#rarry-8=-1#

Add #-8# both sides

#rarry-8+8=-1+8#

#rArry=7#