How do you solve $\frac{y}{4} + 2 = - 1$ $y/4 +2 = -1$ ?

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Answer 1 · 2018-04-24T12:11:48

$y = - 12$ $y = -12$

$\Rightarrow \frac{y}{4} + 2 = - 1$ $=> y/4 + 2 = -1$

Subtract $2$ $2$ from both the sides

$=> y/4\ cancel(+2)\ cancel(-2) = -1 - 2$

$=> y/4 = -3$

Multiply both sides by $4$

$=> y/cancel(4) × cancel(4) = -3 × 4$

$=> y = -12$

Answer 2 · 2018-04-24T12:17:53

$y=-12$

Solve:

$y/4+2=-1$

Multiply both sides by $4$ .

$y/color(green)cancel(color(black)(4))^1xxcolor(green)cancel(color(red)(4))^1+2xxcolor(red)4=-1xxcolor(red)4$

Simplify.

$y+8=-4$

Subtract $8$ from both sides.

$y+color(red)cancel(color(black)(8))-color(red)cancel(color(black)(8))=-4-8$

Simplify.

$y=-12$

How do you solve y/4 +2 = -1y4+2=−1y/4 +2 = -1?