How do you solve # y ≥ 3x + 6#?

1 Answer
Alan P.
Jul 7, 2015

You could draw a graph or rewrite the inequality in terms of #y# as a variable for #x#, but fundamentally #y>=3x+6# is a solution form.

Explanation:

As a graph
graph{y>=3x+6 [-10, 10, -5, 5]}

Rewritten, solving for #x# in terms of #y#
#color(white)("XXXX")##y >= 3x+6#

#color(white)("XXXX")##y-6 >= 3x#

#color(white)("XXXX")##y/3-2 <= x#
or
#color(white)("XXXX")##x<= y/3-2#

Related questions
See all questions in Linear Inequalities in Two Variables
Impact of this question
2891 views around the world
You can reuse this answer
Creative Commons License