How do you solve #y=1/3x + 2# and #y=-4/3x -3# by graphing?

1 Answer
Mark D.
Apr 3, 2018

(-3,1) is where they intersect

Explanation:

Find three sets of coordinates for the first line, plot these three points and join them together. Do the same for the second line and where the two lines cross will be the solution - an #x# value and a #y# value.

If you solve it algebraically you can check your graphing is correct

Equate both equations:

#1/3x +2# = #-4/3x-3#

Add #4/3x# to both sides:

#5/3x +2=-3#

Subtract 2 from both sides:

#5/3x=-5#

Divide both sides by#5/3#:

#x=-3#

Put #x=3# into either equation to find #y#:

#y=(1/3)##xx#-3+2
#y=1#

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