How do you solve #y=-1/2(x+4)^2+4#?

1 Answer
Jim G.
May 4, 2018

#x=-4+-2sqrt2#

Explanation:

#"set "y=0" to solve for x"#

#rArr-1/2(x+4)^2+4=0larrcolor(blue)"subtract 4 from both sides"#

#rArr-1/2(x+4)^2=-4#

#"divide both sides by "-1/2#

#rArr(x+4)^2=(-4)/(-1/2)=8#

#color(blue)"take the square root of both sides"#

#sqrt((x+4)^2)=+-sqrt8larrcolor(blue)"note plus or minus"#

#rArrx+4=+-2sqrt2larrcolor(blue)"subtract 4 from both sides"#

#rArrx=-4+-2sqrt2larrcolor(red)"exact solutions"#

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