How do you solve $x(x+6)=-2$ using the quadratic formula?

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Answer 1 · 2016-02-29T18:29:39

$x(x+6)=-2 , x^2+6x+2=0,a=1,b=6,c=2$
$x=(-6+-sqrt(6^2-4(1)(2)))/2=(-6+-sqrt(28))/2=(-6+-4sqrt7)/2$
$x=-3+-2sqrt7$

First distribute the x into x+6 and then put everything on one side then use the quadratic formula to solve for x.

How do you solve x(x+6)=-2x(x+6)=-2 using the quadratic formula?