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How do you solve #-x=x^2#?

1 Answer

Jul 7, 2016

#x = 0 or x = -1#

Explanation:

Add #x# to both sides.

#x^2 + x = 0#

Factor

#x(x+1) = 0#

In order to satisfy the equation, the left hand side must equal zero. This means that either #x = 0# or #x+1 = 0#

#implies x = 0 or x = -1#

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