How do you solve #(x + 9) ^ { 2} - 36= 0#?

2 Answers
Mark D.
Apr 8, 2018

#x=-3 or -15#

Explanation:

#(x+9)^2#=36

#(x+9)=##\pmsqrt(36)#

#x+9=6# or #x+9=-6#

#x=-3# or #x=-15#

Jim G.
Apr 8, 2018

#x=-15" or "x=-3#

Explanation:

#"subtract 36 from both sides"#

#(x+9)^2cancel(-36)cancel(+36)=0+36#

#rArr(x+9)^2=36#

#color(blue)"take the square root of both sides"#

#rArrx+9=+-sqrt36larrcolor(blue)"note plus or minus"#

#rArrx=-9+-6#

#rArrx=-9-6=-15#

#"or "x=-9+6=-3#

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