How do you solve #x² - 5x + 6 = 0#?

1 Answer
Don't Memorise
Jun 25, 2015

The solutions are
#color(green)(x=2, x=3#

Explanation:

# x^2 - 5x +6=0#
Here we can first factorise the expression and then find the solution:

Factorising by splitting middle term
# x^2 color(green)(-2x - 3x) +6=0#

# x(x-2) -3(x-2)=0#
#color(green)( (x-2)(x-3) =0#
Equating the two factors with zero to obtain solutions:

  • #x-2 = 0 ,color(green)( x=2#
  • #x-3 = 0 , color(green)(x=3#
Related questions
See all questions in Comparing Methods for Solving Quadratics
Impact of this question
179699 views around the world
You can reuse this answer
Creative Commons License