How do you solve $x² = 5x + 10$ using the quadratic formula?

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Answer 1 · 2018-03-16T16:14:03

Read below.

Let's put the variables and the numbers on one side.

We have:

$x^2-5x-10=0$ Since this quadratic equation is in the form $ax^2+bx+c=0$ , $a=1$ , $b=-5$ , and $c=-10$

$x=(-b+-sqrt(b^2-4(a)(c)))/(2a)$ Plug in the values.

$=>x=(-(-5)+-sqrt((-5)^2-4(1)(-10)))/(2*1)$

$=>x=(5+-sqrt(25+40))/2$

$=>x=(5+-sqrt(65))/2$

Your two answers would be $(5-sqrt(65))/2$ and $(5+sqrt(65))/2$

How do you solve x² = 5x + 10x² = 5x + 10 using the quadratic formula?