How do you solve $\frac{x - 4}{x + 5} < 0$ $(x-4)/(x+5)<0$ ?

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Answer 1 · 2016-10-06T17:28:05

$x < 4$ $x<4$

In order to solve this inequality, you have to isolate $x$ $x$ on one side of it.

$\frac{x - 4}{x + 5} < 0$ $(x-4)/(x+5) <0$

First, we multiply both sides by $x + 5$ $x+5$ to remove the fraction

$x - 4 < 0$ $x-4<0$

Then add four to both sides to isolate $x$ $x$

$x < 4$ $x<4$

How do you solve x−4x+5<0(x-4)/(x+5)<0?