How do I solve the rational inequality $(x^2-1)/(x+1)<2$ using a TI-83?

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Answer 1 · 2015-07-08T21:05:32

You can input $Y1=$ function, $Y2=2$ and use intercept.

But you can also do this on a piece of paper.
If you factorise the denominator, you get:

$((x-1)cancel((x+1)))/cancel(x+1)<2$

And you can cancel out the $x+1$ 's on the condition that $x!=-1$ (but that value of $x$ was already 'forbidden').

We are now left with: $x-1<2->x<3$

Complete answer: $x<3andx!=-1$
graph{(x^2-1)/(x+1) [-10, 10, -5, 5]}

How do I solve the rational inequality (x^2-1)/(x+1)<2(x^2-1)/(x+1)<2 using a TI-83?