How do you solve #x+3y=y+110# for y?

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Answer 1 · 2016-09-03T02:05:29

#y=(110-x)/2#

Solve #x+3y=y+110# for #y#.

Subract #x# from both sides of the equation.

#3y=y+110-x#

Subtract #y# from both sides.

#3y-y=110+x#

Simplify #3y-y# to #2y#.

#2y=110+x#

Divide both sides by #2#.

#y=(110-x)/2#