How do you solve #x+3(x+4)=20#?

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Answer 1 · 2016-05-31T23:00:40

You have to expand the equation.

#x + 3x + 12 = 20#

#4x + 12 = 20#

#4x = 20 - 12#

#4x = 8#

#x = 2#

Hopefully this helps!