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How do you solve #| x + 3 | = 5#?

1 Answer

Oct 5, 2016

#color(green)(x=2) or color(green)(x=-8)#

Explanation:

If #abs(x+3)=5#
then #{:("either",x+3=5," or ",x+3=-5), (,rarr x=2,,rarr x=-8) :}#

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