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How do you solve $(x + 3)^2 - 3 = 13$ ?

1 Answer

May 8, 2015

In this way:

$(x+3)^2-3=13rArr(x-3)^2=16rArrx+3=+-4rArr$

$x=-3+-4$

$x_1=-3-4=-7$ ;

$x_2=-3+4=1$ .

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