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How do you solve $(x-3)^2=16$ ?

1 Answer

Aug 23, 2016

$x=7$
$x=-1$

Explanation:

$(x-3)^2=16$

or

$x-3=sqrt16$

or

$x-3=+-4$

or

$x=3+-4$

or

$x=3+4$

or

$x=7$ ----------------------Ans $1$

or

$x=3-4$

or

$x=-1$ -------------------------Ans $2$

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