How do you solve $x² - 3 = 0$ using the quadratic formula?

Question

22169 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-14T14:47:49

For a quadratic with formula $ax^2+bc+c=0$ the solutions are given by

$x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)$

Now for $x^2-3=0$ we have $a=1,b=0,c=-3$ hence

$x_(1,2)=(0+-sqrt(0^2-4*1(-3)))/2=+-sqrt3$

How do you solve x² - 3 = 0x² - 3 = 0 using the quadratic formula?