How do you solve #x²+2x-24=0# algebraically?
1 Answer
Mar 21, 2016
Complete the square to find:
#x=4# or#x=-6#
Explanation:
Complete the square
#a^2-b^2 = (a-b)(a+b)#
with
#0 = x^2+2x-24#
#=x^2+2x+1-1-24#
#=(x+1)^2-5^2#
#=((x+1)-5)((x+1)+5)#
#=(x-4)(x+6)#
So
