How do you solve $x^2-x= -1$ using the quadratic formula?

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Answer 1 · 2016-07-26T15:50:38

$x=(1+-isqrt(3))/2$

The quadratic formula for a general quadratic equation $ax^2+bx+c=0$ is given by:

$x=(-b+-sqrt(b^2-4ac))/(2a)$

For the equation:

$x^2 - x = -1$

or $x^2 -x + 1=0$

you get

$a=1; b=-1 and c = 1$

by substituting these values in the quadratic formula:

$x=(-(-1)+-sqrt((-1)^2-4*1*1))/(2*1)$

$x= (1+-sqrt(1-4))/2$

or $x=(1+-sqrt(-3))/2$

or $x=(1+-isqrt(3))/2$

How do you solve x^2-x= -1x^2-x= -1 using the quadratic formula?