How do you solve $x^{2} - 9 x + 14 = 0$ $x^2-9x+14=0$ ?

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Answer 1 · 2015-02-04T16:20:50

Solve $x^{2} - 9 x + 14 = 0$ $x^2- 9x + 14 = 0$ .

The answer is $x = 7$ $x = 7$ and $x = 2$ $x = 2$ .

Factor the left side of the equation.
$(x - 7) (x - 2) = 0$ $(x - 7)(x- 2) =0$

Solve each term in the product separately.
$x - 7 = 0$ $x - 7 = 0$
Add 7 to both sides.
$x = 7$ $x = 7$

$x - 2 = 0$ $x - 2 = 0$
Add 2 to both sides.
$x = 2$ $x = 2$

Check.
$x = 7$ $x= 7$
$7^{2} - 9 (7) + 14 = 0$ $7^2 - 9(7) + 14 = 0$
$49 - 63 + 14 = 0$ $49 - 63 + 14 = 0$

$x = 2$ $x = 2$
$2^{2} - 9 (2) + 14 = 0$ $2^2 - 9(2) + 14 = 0$
$4 - 18 + 14 = 0$ $4 - 18 + 14 = 0$

How do you solve x2−9x+14=0x^2-9x+14=0?