How do you solve $x^2 - 8x + 2 = 0$ using the quadratic formula?

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Answer 1 · 2017-06-03T10:36:11

7.74, 0.26

As per quadratic formula, $x =[-b+-sqrt(b^2-4ac)]/[2a]$ here, a = 1, b = - 8 & c= 2

Put all these values, we get $x = [-(-8)+- sqrt{(-8)^2-4*1*2}]/[2*1]$

$rArr x = [+8 +- sqrt(64-8)]/2$

$rArr x = [8+- sqrt56]/2$

$rArr x = [8+-7.48]/2$

$rArr x = (8+7.48)/2, (8-7.48)/2$

$rArr x = 15.48/2, 0.52/2$

$rArr x = 7.74, 0.26$

How do you solve x^2 - 8x + 2 = 0x^2 - 8x + 2 = 0 using the quadratic formula?