How do you solve $x^2+8x-2=0$ using the quadratic formula?

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How do you solve $x^2+8x-2=0$ using the quadratic formula?

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Answer 1 · 2016-03-27T04:59:47

$- 4 +- 3sqrt2$

Explanation:

Use the improved quadratic formula (Google, Yahoo Search).
$D = d^2 = b^2 - 4ac = 64 + 8 = 72$ --> $d = +- 6sqrt2$
There are 2 real roots:
$x = -b/(2a) +- d/(2a) = -8/2 +- (6sqrt2)/2 = - 4 +- 3sqrt2$

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How do you solve $x^2+8x-2=0$ using the quadratic formula?

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How do you solve x^2+8x-2=0 x^2+8x-2=0 using the quadratic formula?

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How do you solve $x^2+8x-2=0$ using the quadratic formula?