How do you solve x^2+8x=12 using the quadratic formula?

1 Answer
Jul 9, 2015

x ={-4+2sqrt(7) , -4-2sqrt(7)}

Explanation:

The equation is x^2-8*x-12=0
The quadratic equation is:
x =( -b +- sqrt(b^2-4*a*c)) / (2*a)
Here, a = 1, b = 8, c = -12
Substituting these values,

x = (-8 +- sqrt((-8)^2 + 48)) / (2*1) = (-8 +- sqrt(112)) / 2 = -4+-2sqrt(7)

Thus the answer is x ={-4+2sqrt(7) , -4-2sqrt(7)}