How do you solve $x^2 – 7x – 1 = -7$ using the quadratic formula?

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Answer 1 · 2016-02-16T08:58:40

Solution is $6$ and $1$

For an equation $ax^2+bx+c=0$ , quadratic formula gives the solution as $(-b+-sqrt(b^2-4ac))/(2a)$ .

As in the given equation $x^2-7x-1=-7$ or $x^2-7x+6=0$ i.e. $a=1, b=-7$ and $c=6$

Solution is given by $(-(-7)+-sqrt((-7)^2-4*1.6))/(2*1)$ or

$(7+-sqrt(49-24))/2$ or $(7+-sqrt25)/2$ or $(7+-5)/2$

Hence solution is $6$ and $1$

How do you solve x^2 – 7x – 1 = -7x^2 – 7x – 1 = -7 using the quadratic formula?