How do you solve $x^2−(72)x+32=0$ using the quadratic formula?

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Answer 1 · 2016-03-07T13:12:32

$x_1=0,45$
$x_2=71,55$

$ax^2+bx+c=0$
$Delta=b^2-4*a*c$
$Delta=(-72)^2-4*1*32" "Delta=5184-128" "Delta=5056$
$x_1=(-b-sqrt Delta)/(2a)" "x_1=(72-71,1)/(2*1)$
$x_1=(0,9)/2$

$x_2=(-b+sqrt Delta)/(2a)$
$x_2=(72+71,1)/(2.1)$
$x_2=(143,1)/2$

How do you solve x^2−(72)x+32=0 x^2−(72)x+32=0 using the quadratic formula?