How do you solve $x^2 -5x= -7$ using the quadratic formula?

Question

5263 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-16T03:10:46

Add $7$ to both sides of the equation to make it equal to $0$ :

$x^2 - 5x + 7 = 0$

Then use the quadratic formula and plug in the values:

$x = (-b +-sqrt(b^2-4ac))/(2a)$

$x = (5 +-sqrt(25-4(1)(7)))/(2(1)) = (5+-sqrt(-3))/2$

If you've learned about complex numbers, this can be simplified to

$x = 5/2 +- (isqrt(3))/2$

How do you solve x^2 -5x= -7x^2 -5x= -7 using the quadratic formula?