How do you solve $x^{2} + 5 x + 3 = 9$ $x^2 + 5x + 3 = 9$ ?

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How do you solve $x^{2} + 5 x + 3 = 9$ $x^2 + 5x + 3 = 9$ ?

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Answer 1 · 2018-07-02T04:46:23

$x = - 6, x = 1$ $x = -6, x = 1$

Explanation:

Given: $x^{2} + 5 x + 3 = 9$ $x^2 + 5x + 3 = 9$

Solve means to find the values of $x$ $x$ that make the equation true.

Put the equation in the form: $A x^{2} + B x + C = 0$ $Ax^2 + Bx + C = 0$ by subtraction $9$ $9$ from both sides of the equation:

$x^{2} + 5 x - 6 = 0$ $x^2 + 5x -6 = 0$

Factor the equation by finding two numbers that multiply to

$ul(A*C = -6 " and sum to " B = 5)$
$-2 * 3 = -6 " "-2+3 = 1" doesn't work"$
$-6 * 1 = -6 " "-6 + 1 = -5" doesn't work"$
$6 * -1 = -6 " " 6 + -1 = 5" works"$

$x^2 + 5x -6 = 0 => " "(x+6)(x-1) = 0$

$x + 6 = 0; " " x - 1 = 0$

$x = -6, x = 1$

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How do you solve $x^{2} + 5 x + 3 = 9$ $x^2 + 5x + 3 = 9$ ?

1 Answer

Explanation:

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How do you solve x^2 + 5x + 3 = 9x2+5x+3=9x^2 + 5x + 3 = 9?

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How do you solve $x^{2} + 5 x + 3 = 9$ $x^2 + 5x + 3 = 9$ ?