How do you solve $x^2 – 5x – 3 = -7$ using the quadratic formula?

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Answer 1 · 2017-01-19T17:41:26

$x=1$ or $x=4$

$x^2-5x-3=-7$

Add $7$ to each side.

$x^2-5x+4=0$

Factorise.

$x^2-4x-x+4=0$

$x(x-4)-1(x-4)=0$

$(x-1)(x-4)=0$

$x-1=0$ or $x-4=0$

$x=1$ or $x=4$

How do you solve x^2 – 5x – 3 = -7x^2 – 5x – 3 = -7 using the quadratic formula?