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How do you solve #x^2-5x+3=0# using the quadratic formula?

1 Answer

Sep 23, 2016

#x = (5 pm sqrt(13)) / (2)#

Explanation:

We have: #x^(2) - 5 x + 3 = 0#

#=> x = (- (- 5) pm sqrt((- 5)^(2) - 4 (1) (3))) / (2 (1))#

#=> x = (5 pm sqrt(25 - 12)) / (2)#

#=> x = (5 pm sqrt(13)) / (2)#

Therefore, the solutions to the equation are #x = (5 - sqrt(13)) / (2)# and #x = (5 + sqrt(13)) / (2)#.

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