How do you solve x^2-5x=-20 solve equation using quadratic formula?

1 Answer
Nallasivam V
Jan 13, 2017

x=(5+-isqrt(55))/2

Explanation:

Given -

x^2-5x=-20

x^2-5x+20=0

x=(-b+-sqrt(b^2-4ac))/(2a)

x=(-(-5)+-sqrt((-5)^2-(4 xx 1 xx 20)))/(2 xx 1)

x=(5+-sqrt((25-80)))/2

x=(5+-sqrt(-55))/2

x=(5+sqrt(-55))/2
x=(5-sqrt(-55))/2

x=(5+-isqrt(55))/2

Related questions
See all questions in Quadratic Formula
Impact of this question
3779 views around the world
You can reuse this answer
Creative Commons License