How do you solve $x^2+5x-2=0$ using the quadratic formula?

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How do you solve $x^2+5x-2=0$ using the quadratic formula?

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Answer 1 · 2016-03-31T04:07:37

$x = -5/2 +- sqrt33/2$

Explanation:

$y = x^2 + 5x - 2 = 0$
Use the improved quadratic formula (Google, Yahoo Search)
$D = d^2 = b^2 - 4ac = 25 + 8 = 33$ --> $d = +- sqrt33$
There are 2 real roots.
$x = -b/(2a) +- d/(2a) = -5/2 +- sqrt33/2$

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How do you solve $x^2+5x-2=0$ using the quadratic formula?

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How do you solve x^2+5x-2=0x^2+5x-2=0 using the quadratic formula?

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How do you solve $x^2+5x-2=0$ using the quadratic formula?