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How do you solve $x^2-4x-2=0$ ?

1 Answer

Aug 9, 2015

$x=2+-sqrt(6)$

Explanation:

Complete the square for $x$ :
$x^2-4x-2=(x-2)^2-6=0$

Then rearrange to make $x$ the subject:
$x-2=+-sqrt(6)=>x=2+-sqrt(6)$

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