How do you solve $x^{2} - 4 = 76$ $x^2-4=76$ ?

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How do you solve $x^{2} - 4 = 76$ $x^2-4=76$ ?

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Answer 1 · 2017-02-13T23:43:10

See the entire solution process below:

Explanation:

First, add $4$ $color(red)(4)$ to each side of the equation to isolate the $x^{2}$ $x^2$ term while keeping the equation balanced:

$x^{2} - 4 + 4 = 76 + 4$ $x^2 - 4 + color(red)(4) = 76 + color(red)(4)$

$x^{2} - 0 = 80$ $x^2 - 0 = 80$

$x^{2} = 80$ $x^2 = 80$

Now, take the square root of each side of the equation to solve for $x$ $x$ while keeping the equation balanced. Remember, when taking the square root of a number there will be a negative and positive solution:

$\sqrt{x^{2}} = \pm \sqrt{80}$ $sqrt(x^2) = +-sqrt(80)$

$x = \pm \sqrt{80} = \pm 8.944$ $x = +-sqrt(80) = +-8.944$ rounded to the nearest thousandth

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How do you solve $x^{2} - 4 = 76$ $x^2-4=76$ ?

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How do you solve $x^{2} - 4 = 76$ $x^2-4=76$ ?