How do you solve $x^2-3x+2=0$ using the quadratic formula?

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Answer 1 · 2018-05-02T15:05:37

$x_1=2 or x_2=1$

$x^2+px+q=0$
$x_(1,2)=-p/2+-sqrt((p/2)^2-q)$
$p=-3 and q=2$
$x_(1,2)=3/2+-sqrt(9/4-2)$
$x_1=3/2+1/2=2 or x_2=3/2-1/2=1$

How do you solve x^2-3x+2=0x^2-3x+2=0 using the quadratic formula?