How do you solve $x^2 + 3x -10 =0$ using the quadratic formula?

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Answer 1 · 2016-03-25T17:56:42

The solutions are:
$x= 2$

$x= -5$

$x^2 + 3x - 10= 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:

$a=1, b= 3 , c= - 10$

The Discriminant is given by:

$color(blue)(Delta=b^2-4*a*c$

$= (3)^2-(4* 1 * ( -10))$

$= 9 + 40 = 49$

The solutions are found using the formula
$color(blue)(x=(-b+-sqrtDelta)/(2*a)$

$x = ((-3)+-sqrt(49))/(2*1) = (-3 +- 7 )/2$

$x= (-3 + 7 )/2 = 4/2 = 2$

$x= (-3-7)/2 = -10/2 = -5$

How do you solve x^2 + 3x -10 =0x^2 + 3x -10 =0 using the quadratic formula?