How do you solve #x^2+3x-10=0#?
1 Answer
Aug 1, 2015
Solve y = x^2 + 3x - 10 = 0
Ans: 2 and -5
Explanation:
Find 2 numbers knowing sum (-3) and product (-10).
Factor pairs of (-10) -> (-2, 5). This sum is 3 = b. Then the opposite numbers 2 and -5 are the real roots.