How do you solve $x^2+3x+1=0$ using the quadratic formula?

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Answer 1 · 2016-04-07T16:12:45

Solution is given by irrational numbers $(-3+sqrt5)/2$ and $(-3-sqrt5)/2$ .

The solution of a quadratic equation $ax^2+bx+c=0$ , using quadratic formula is given by $(-b+-sqrt(b^2-4ac))/(2a)$

Hence the solution of $x^2+3x+1=0$ is given by

$x=(-3+-sqrt(3^2-4*1*1))/(2*1)$ or

$x=(-3+-sqrt(9-4))/2=(-3+-sqrt5)/2$

Hence solution is given by irrational numbers $(-3+sqrt5)/2$ and $(-3-sqrt5)/2$ .

How do you solve x^2+3x+1=0x^2+3x+1=0 using the quadratic formula?