How do you solve $x^2-2x=5$ using the quadratic formula?

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How do you solve $x^2-2x=5$ using the quadratic formula?

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Answer 1 · 2017-05-02T16:13:32

$x=4$ and $x=0$

Explanation:

In quadratic equations we have a formulae to find the roots of the quadratic expression $ax^2+bx+c=0$ that is:
$x=[(-b)+-(sqrt(b^2-4ac))]/(2a)$
So extracting the values from the given above equation and substituting we get
$x=[-(-2)+-(sqrt(((-2)^2)-4(1)(-5)))]/[2(1)]$
$x=(2-2)/2$ , $x=(2+2)/2$
$=>x=4,0$

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How do you solve $x^2-2x=5$ using the quadratic formula?

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