How do you solve $x^2 - 2x + 4$ using the quadratic formula?

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Answer 1 · 2015-07-05T13:51:18

$x^2-2x+4 = 0$ has no real solutions, only complex ones, but the quadratic formula does work to give:

$x = 1+-isqrt(3)$

$x^2-2x+4$ is of the form $ax^2+bx+c$

with $a=1$ , $b=-2$ and $c=4$

The quadratic formula gives us the solutions to $x^2-2x+4$ as:

$x = (-b +- sqrt(b^2-4ac))/(2a)$

$=(2 +-sqrt(2^2-(4xx1xx4)))/2$

$=(2+-sqrt(-12))/2$

$=(2+-2sqrt(-3))/2$

$=1+-isqrt(3)$

How do you solve x^2 - 2x + 4 x^2 - 2x + 4 using the quadratic formula?