How do you solve x^2= -2x + 3 using the quadratic formula?

1 Answer
seol
Feb 27, 2017

x=-3,1

Explanation:

x^2=-2x+3
subtract x^2 from each side so you get 0 on the left
0=-x^2-2x+3
apply quadratic equation
x=(-b\pm\sqrt(b^2-4ac))/(2a)\rArr(-(-2)\pm\sqrt((-2)^2-4(-1)(3)))/(2(-1))
simplify and solve for x
x=(2\pm\sqrt(4+12))/(-2)=(2\pm\sqrt(16))/(-2)=(2\pm4)/(-2)
(2+4)/-2\larrx\rarr(2-4)/-2

therefore, x is either of the following...
x=6/-2=-3
x=(-2)/-2=1

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