How do you solve $x^{2} - 25 = 0$ $x^2 - 25 = 0$ ?

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How do you solve $x^{2} - 25 = 0$ $x^2 - 25 = 0$ ?

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Answer 1 · 2015-06-12T18:08:52

$x_{1} = + 5$ $x_1=+5$
$x_{2} = - 5$ $x_2=-5$

Explanation:

Take $25$ $25$ to the right:
$x^{2} = 25$ $x^2=25$ square root both sides to get:
$x = \pm \sqrt{25}$ $x=+-sqrt(25)$
So you get two possible solutions:
$x_{1} = + 5$ $x_1=+5$
$x_{2} = - 5$ $x_2=-5$

You can also use the Quadratic Formula but this is faster.

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How do you solve $x^{2} - 25 = 0$ $x^2 - 25 = 0$ ?

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Explanation:

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